A Bag Contains Red And Blue Marbles Two Marbles Are Drawn Without Replacement

Two marbles are randomly drawn without replacement.

A bag contains red and blue marbles two marbles are drawn without replacement. Two marbles are drawn without replacement from an urn containing 4 red marbles 5 white marbles and 2 blue marbles. A bag contains 3 white 4 black and 2 red marbles. Drawing simultaneously is the same as sampling without. Can someone please point why my solution is wrong.

B find probabilities for p bb p br p rb p ww p at least one red p exactly one red 3. Determine the probability that at least one is red. On the other hand there are 9 choices for the first marble and 8. The probability of selecting a red marble and then a blue marble is 0 28.

P both red p second is red. A bag contains red and blue marbles. Then there are 4 possibilities for drawing the first red marble and 3 possibilities for drawing the second red marble. P at least one red p rr or rb or br alternatively p at least one red 1 p no reds complementary events 1 p bb and so on.

Determine the probability that. Two marbles are drawn without replacement. Number the red marbles 1 4 and the blue marbles 5 9. The first marble drawn is red and the second is blue.

A bag contains 4 red marbles and 5 blue marbles. A jar contains 4 black marbles and 3 red marbles. The first marble drawn is blue and the second is red. The probability of selecting a red marble on the first draw is 0 5.

What is the probability of selecting a blue marble on the second draw given that the first marble drawn was red. I disagree with the given answer frac29. If replacement is not allowed what is the probability that the second marble drawn will be red. A bag contains 5 red and 3 blue marbles.

Two marbles are drawn simultaneously from the bag. P both red frac binom22. Two marbles are drawn without replacement from a jar containing 4 black and 6 white marbles.